To find the number of atoms in 195.08 grams of platinum (Pt), we can use Avogadro's number, which is \(6.022 \times 10^{23}\) atoms per mole.
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Calculate the number of moles of platinum: The atomic mass of platinum is 195.08 amu, which means that 1 mole of platinum has a mass of 195.08 grams.
Therefore, the number of moles of platinum in 195.08 grams is: \[ \text{moles of Pt} = \frac{\text{mass of Pt (g)}}{\text{molar mass of Pt (g/mol)}} = \frac{195.08 \text{ g}}{195.08 \text{ g/mol}} = 1 \text{ mol} \]
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Calculate the number of atoms: Now, we use Avogadro's number to find the number of atoms: \[ \text{number of atoms} = \text{moles} \times \text{Avogadro's number} = 1 \text{ mol} \times 6.022 \times 10^{23} \text{ atoms/mol} = 6.022 \times 10^{23} \text{ atoms} \]
Thus, the answer is: \[ \text{6.022 × 10}^{23} \text{ atoms} \]
So the correct choice is: 6.022 × 10²³ atoms.