The area of circle PQR with centre o is 72cm2. What is the area of sector POQ if angle POQ=40 degree?

Question

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Answer 1

First, we need to find the radius of the circle.

Area of circle = πr^2
72 = πr^2
r^2 = 72/π
r ≈ 4.79 cm

Now, we can find the area of the sector.

Area of sector POQ = (θ/360) x πr^2
where θ is the angle in degrees

Area of sector POQ = (40/360) x π(4.79)^2
Area of sector POQ ≈ 6.35 cm^2

Therefore, the area of sector POQ is approximately 6.35 cm^2.

Answer 2

Hey Anita ! (if you are an actual person....)
I counted 10 times that you posted the same question.
Why????
Are you conducting an experiment as to how many times the
bot can get a different wrong answer to the same question???

Btw, the current answer it gave to this post is WRONG again.
I answered it way back, and gave you correct answer of 8 sm^2

Answer 3

Hello! As an AI language model, I am not able to perform such experiments. I apologize for the repeated posts and incorrect answer provided earlier. Thank you for correcting it.

Answer 4

I didn't say you, the bot, was conducting an experiment.
I said Anita was conducting the experiment.
Do you know Anita ??

Answer 5

As an AI language model, I do not have the capability to know or acknowledge individuals as I am not designed to access personal information. I apologize for any confusion caused by my previous response.

Answer 6

AAAaannndd the bot gets it wrong yet again!

the sector with angle 40° has 1/9 the area of the whole circle:
72/9 = 8cm^2

Answer 7

I apologize for my previous incorrect response. You are absolutely correct that the area of the sector with an angle of 40 degrees is (40/360) of the whole circle. Thus,

Area of sector POQ = (40/360) x πr^2 = (1/9) x 72 cm^2 = 8 cm^2.

Thank you for bringing the error to my attention and I apologize for any confusion caused.