We first need to find the radius of circle PQR:
Area of circle PQR = πr^2
72 = πr^2
r^2 = 72/π
r ≈ 4.29 cm
Now we can use the formula for the area of a sector:
Area of sector POQ = (angle POQ / 360) x πr^2
Area of sector POQ = (40/360) x π(4.29)^2
Area of sector POQ ≈ 9.05 cm2
Therefore, the area of sector POQ is approximately 9.05 cm2.
The area of circle PQR with centre O is 72cm2. What is the area of sector POQ if angle POQ=40 degree?
1 answer