The area of a triangle , whose base and the corresponding altitude are 15 cm and 7 cm, is equal to area of a right triangle whose one of the sides containing the right angle is 10.5 cm, Find the other side of this triangle.

Question

Ans.= area=15×7=105
105-10.5=00

Answer 1

Area of first triangle = (1/2)(15)(7) = 105/2
area of 2nd triangle = (1/2)(10.5)h

(1/2)(10.5)h = 105/2
10.5h = 105
h = 105/10.5 = 10

Answer 2

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