an altitude of triangle is 5/3rd of the length of its corresponding base if their altitude be increased by 4cm and the base is decreased by 2cm, the area of the triangles remain the same. find the base and altitude of triangle ?????
2 answers
math
let base=x
altitude=5x/3
area= (altitude*base)/2
area of original triangle= (5x^2/3)/2
according to the question
new base=x-2
new altitude=(5x 12)/3
now
area of original triangle=area of new triangle
5x^2/3=5x^2/3-10x/3 4x-8 (1/2 is cancelled from both sides)
now after solving we get
x=12 that is base
and altitude= 20
altitude=5x/3
area= (altitude*base)/2
area of original triangle= (5x^2/3)/2
according to the question
new base=x-2
new altitude=(5x 12)/3
now
area of original triangle=area of new triangle
5x^2/3=5x^2/3-10x/3 4x-8 (1/2 is cancelled from both sides)
now after solving we get
x=12 that is base
and altitude= 20
1 answer