The area of a right triangle is 44m squared. Find the lengths of its legs if one of the legs is 3m longer than the other.

2 answers

(1/2)x(x+3) = 44
x is the shorter of the two legs
x^2 + 3x -88 = 0
That factors easily. (Think 11 x 8)
Take the positive root.
Formula needed is:

A = 1/2(base)(height)

44 = 1/2(x + 3)(x)

One leg is 3m longer than the other can be expressed as (x + 3).

The other leg is simply the letter (x).

In other words, (x + 3) is one of the legs and the letter (x) is the other leg.

This is your equation:

44 = 1/2(x + 3)(x)

Can you solve for x?

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