The angles of elevation θ and ϕ to an airplane are being continuously monitored at two observation points A and B, respectively, which are 5 miles apart, and the airplane is east of both points in the same vertical plane. (Assume that point B is east of point A.)
Write an equation giving the distance d between the plane and point B in terms of θ and ϕ.
3 answers
is someone going to help me? i need help
I answered this
angle B = 180 - ϕ
angle P = 180 - θ - (180 - ϕ) = ϕ - θ
so
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sin (ϕ - θ)/ 5 = sin θ / d
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angle B = 180 - ϕ
angle P = 180 - θ - (180 - ϕ) = ϕ - θ
so
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sin (ϕ - θ)/ 5 = sin θ / d
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Since you didn't like my other formula, let's try this:
If the plane is at height h, then
h = 5/(cotθ-cotϕ)
d = h/sinϕ = 5/(sinϕ(cotθ-cotϕ))
Equivalent trig expressions can be massaged to appear very different
If the plane is at height h, then
h = 5/(cotθ-cotϕ)
d = h/sinϕ = 5/(sinϕ(cotθ-cotϕ))
Equivalent trig expressions can be massaged to appear very different
15 answers