F = k*deltax
F=force
k= spring constant
deltax= change in distance
find spring constant k:
5lb = k*(12-18)in
k = 5lb / (12-18)in
k= -0.8333 lb/in
force to compress spring to 9inches:
F = -0.8333lb/in * (9-18)in
The amount of force required to compress a spring is inversely proportional to the distance that it has been compressed. For one certain spring, it takes 5 pounds of force to compress it from its natural length of 18 inches down to 12 inches. How much force would be required to compress the spring down to 9 inches? Thank you. Is there a formula for this not sure how to approach it...
2 answers
Sorry, I didn't solve it in a calculus manner.
F= ∫kdx with upper and lower limits of distance
Integrating:
F= k*(x_f - x_i)
x_f = final distance , x_i = initial distance
and the rest should be the same as above post.
F= ∫kdx with upper and lower limits of distance
Integrating:
F= k*(x_f - x_i)
x_f = final distance , x_i = initial distance
and the rest should be the same as above post.
1 answer