Since you labeled your subject as vectors I will use them
let the wind vector be (rcosØ, rsinØ
(rcosØ, rsinØ) + (200cos180,200sin180) = (180cos170,180sin170)
( rcosØ, rsinØ) = (22.7346 , 31.2567)
2r^2 = 22.7346^2 + 31.2567^2
r = 27.3299
Ø = 126.03°
My diagram shows sides of 200 and 180 with a 10° angle between them
by the cosine law:
x^2 = 200^2 + 180^2 - 2(200)(180)cos 10°
= 1493.8417..
x = 38.65 km
The air velocity of helicopter Hal is 200km/h due west. Hal's ground velocity is 180km/h in the direction N80*W. Determine the wind velocity.
Please help! I know i should be drawing a diagram but I am very confused with how to do this question!
Thank you!
2 answers
ignore the first part of my solution, start with
My diagram ...
My diagram ...