Use the equation for activation complex: fraction=e^-[activation energy/8.314J/mol*temperature
(also, simply put: f=e^-(Ea/Rt) )
(I'm a chem student learning/studying this at the moment)
The activation energy for the isomerization of methyl isonitrile is 160 kJ/mol. Calculate the fraction of methyl isonitrile molecules that have an energy of 160 or greater at 500 K? 510 K? What is the ratio of the fraction at 510K to that at 500K?
I missed this lesson today and would really appreciate someone explaining how to solve this. Thanks =]
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