The acceleration function (in m/s2) and the initial velocity v(0) are given for a particle moving along a line.

Question

a(t) = 2t + 2,    v(0) = −3,    0 ≤ t ≤ 5
(a) Find the velocity at time t.
v(t) = ______ m/s
(b) Find the distance traveled during the given time interval.
_____ m

Thank you!

Answer 1

v(t) = ∫a(t) dt = ∫(2t+2) dt = t^2+2t+C
v(0) = -3, so C = -3
v(t) = t^2+2t-3

s(t) = ∫[0,5] v(t) dt = ...

Answer 2

The first part was correct and I got 155/3 m for B however, my homework system won't take that answer and doesn't want it as a decimal either. That is the answer, correct?

Answer 3

NO - I did this last night

The thing moves backwards from zero
then forward again

You found the displacement, not the distance.

Answer 4

https://www.jiskha.com/display.cgi?id=1512879704

Answer 5

That was my bad, but he should have read and analyzed your solution.