I hope you know a little calculus.
dv/dt=a
v= INT a dt=9t^2-4t + vo
2= 9t^2-4t + 2
0=t(9t-4)
t= 4/9 sec
The acceleration am/s^2 of a particle moving in a straight line is given by a = 18t – 4, where t is time in seconds. The initial velocity of the particle is 2 m/s
a) Find the expression for velocity in terms of t
b) Determine the time when the velocity is again 2m/s
1 answer
1 answer