3+5d = 2(3+2d)
3+5d = 6+4d
d = 3
So, the sequence is
3, 6, 9, 12, 15, 18, 21, 24, 27, 30 ...
The 6th term of an A.P is twice the third and the first term is 3. Find the common difference and the 10th term.
11 answers
as d=3
a10=3+(10-1)3
=30
a10=3+(10-1)3
=30
3+5d=2(3+2d)
3+5d=6+4d
d=3
Imply formula to get the sequence
3+5d=6+4d
d=3
Imply formula to get the sequence
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In an arithmetic sequence is eighth term is twice the fourth term the twenty term is 20 . common difference