the 2nd term of a g.p is 12 more than the 1st term,given that the common ratio is half of the 1st term find the third term of the g.p

Answer 1

Given:
t2 = t1 + 12.......Eq 1
r = (1/2) × t1........Eq 2

Solution:
Since it's a geometric progression, we know that:
t2 = t1 × r ........Eq 3

Substitute Eq 2 into Eq 3:
t2 = t1 × (1/2) × t1 ....... Eq 4

Substitute Eq 1 into Eq 4:
t1 + 12 = t1 × (1/2) × t1

Solve for t1, and you will now have enough info to find t3.

Answer 2

Pls how do I solve for t1