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Find the average of two adjacent midpoints; for example: (29.5 + 39.5)/2 = 34.5 34.5 is the class boundary between the two classes whose midpoints are 29.5 and 39.5. Drop and raise that value a half-point for the class limits: 34.5 - .5 = 34 34.5 + .5 = 35
The random variable is her score. Adding up the probabilities is one way to check if it's a valid model. Here's an example of calculating Expected Value for roll of a die: E[X] = 1(1/6) + 2(1/6) + ... + 6(1/6) = 3 1/2 You can use a similar process on your
Yes, that's correct.
Try some combinations to see which one gives the greatest probability of Gg offspring. For example, if one parent has GG and the other has Gg, the possible offspring outcomes are GG, Gg, GG, Gg. So this would be a 50 % probability of offspring having Gg.
Your derivative is almost correct. 100 should appear only once, as it is a common factor of both terms.
Various measures are used to compare 2 data sets. For example, the mean (average).
Standard deviation is a measure of how spread out, or variable, the data is.
A 1-inch margin on all four sides of an 8 1/2 in. by 11 in. piece of paper leaves a 6 1/2 in. by 9 in. piece of paper to work with. a) The painting is in landscape orientation, 30 in. wide by 22.5 in. tall. The usable paper is in portrait orientation, 6
Given: a+b=c .... Eq 1 a+c=d .... Eq 2 b=c+d .... Eq 3 { d ε Z | d > 0 } Maximum value of a = ? Sub Eq 3 into Eq 1: a + (c + d) = c a = - d .... Eq 4 At this point, ask yourself "what value of d (remembering that d is a positive integer) will yield the
Yes, that's correct.
Liking pancakes and liking bacon are not mutually exclusive events, because some people like both. Therefore, P(P or B) = P(P) + P(B) - P(P and B) = [(21 + 31) + (23 + 31) - (31)]/100 = ?
He is investing both amounts for the same amount of time, and both at simple interest rates. The only differentiating factor here is the interest rate, so it would make sense for him to invest as much as possible in corporate bonds, because they earn the
Given: t2 = t1 + 12.......Eq 1 r = (1/2) × t1........Eq 2 Solution: Since it's a geometric progression, we know that: t2 = t1 × r ........Eq 3 Substitute Eq 2 into Eq 3: t2 = t1 × (1/2) × t1 ....... Eq 4 Substitute Eq 1 into Eq 4: t1 + 12 = t1 × (1/2)
Math - Probability Let the number of red balls in the box be x. Then the number of blue balls in the box is x + 4. Hence the total number of balls in the box is 2x + 4. P(R) = x/(2x + 4) P(B) = (x + 4)/(2x + 4) Thus P(2 different colours, with
