The 10th term of an arithmetic progression is 68 and the common difference is 7 find first term of a sequence
6 answers
How to solve it
d=7
a_10 = a+9d
so
a+63 = 68
a = 5
a_10 = a+9d
so
a+63 = 68
a = 5
Thanks a lot
how did a is 5 a=5
The 10term of of arithmetic progression is 68 and the common difference is 7,find the first term born the sequence
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