What, this question too hard for the bot,
how come it is not answering it?
1.
term(10) = 68, d = 7
a + 9d + 68
a + 63 = 68
a = 5
2.
ar = 9
ar^3 = 81
divide one by the other
r^2 = 9
r = + 3
if r = 3, a = first term = 3 ..... if r = -3, a = -3
term10 = ar^9 = 3(3)^9 = 59049 , for both values of a and r
1.The tenth term of an arithmetic progression is68 and the common difference is 7 find the term
2.the second term of an exponential sequence is9 while the 4th term is 81find:
A:first term b, common ratio c,10th term
1 answer
1 answer