Thanks for the help with my previous problems.
The acceleration to gravity on the moon is 1.6m/sec^2.
If a rock is dropped into a crevasse, how fast it will be going just before it hits bottom 30 sec later?
How far below the point of release is the bottom of the crevasse?
If instead of being released from the rest, the rock is thrown into the crevasse from the same point with a downward velocity of 4 m/s, when will it hit the botoom and how fast will it be going when it does.
Any guidance is appreciated.
Formulas:
vfinal= vinitial + acceleration*time
finalposition= initialposition + vinitial*time + 1/2 acceleration*time^2
The acceleration to gravity on the moon is 1.6m/sec^2. acceleration is given, downward, lets call that the negative direction. acceleration = -1.6m/s^2
If a rock is dropped into a crevasse, how fast it will be going just before it hits bottom 30 sec later? initial velocity= 0. Time is 30 sec.
veloictyfinal= initialvelocity + acceleration *time.
If you did this right, the velocity final is negative, meaning it is downward
How far below the point of release is the bottom of the crevasse?
finalposition= initialposition + vinitial*time + 1/2 acceleration*time^2
If instead of being released from the rest, the rock is thrown into the crevasse from the same point with a downward velocity of 4 m/s, when will it hit the botoom and how fast will it be going when it does. here initial velocity is -4m/s.
Use the distance found in the second part, the distance in the crevice cant change. Solve for time (note: it is a quadratic, use quadratic equation). Once time is found, solve for the final velocity.
For the last part, do we use the same formula, that is vfinal= vinitial + acceleration*time, to get the quadratic equation?
No. You know vinitial, you know acceleration, and you just found time. So it is a plug and chug.
So I find time using the formula, v = d/t ?
That is t = d/v = 720/4 = 180
And v(final) = v(initial) + acceleration * time^2
v(final) = -4 + 1.6 * (180)^2
I am lost!
I am supposed to get 27.60 sec & 48.166 m/s
Find time using the quadratic you just had. Once time is found,
vfinal=vinitial+ acceleraiton*time.
Memorize those two formulas I started you out with. Use flashcards. In this last post, you typed it wrong (see above), you cant afford that. Memorize them now.
But there are two unknowns in the equation, right? time and v(final). How do you get the quadratic?
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