Hi:
You are correct. The test criteria are,
1) The terms a_n are of decreasing sequence; clearly 1/(3n+1) is decreasing on [1, inf].
2) Limit(n->inf)[a_n] = 0.
Both criteria having been met, we conclude convergence.
Regards,
Rich B.
test the series for convergence or divergence using the alternating series test
the sum from n=1 to infinity of (-1)^n/(3n+1)
I said it converges, is this true?
2 answers
"If the sequence An converges to 0, and each An is smaller than An-1 (i.e. the sequence An is monotone decreasing), then the series converges."
In this case, An = 1 / (3n + 1)
The limit as n->infinity (An) = 0
A1 = 1 / 4
A2 = 1 / 7
Therefore, by the Alternating Series Test the series converges.
In this case, An = 1 / (3n + 1)
The limit as n->infinity (An) = 0
A1 = 1 / 4
A2 = 1 / 7
Therefore, by the Alternating Series Test the series converges.
0 answers