Volume of the can = πr2h
r = radius of the can = 2.6/2 = 1.3 inches
h = height of the can = 3 x 2.6 = 7.8 inches
Volume of the can = π(1.3)2(7.8) = 44.7 cubic inches
Volume of the 3 tennis balls = 3 x (4/3)πr3
r = radius of the tennis ball = 2.6/2 = 1.3 inches
Volume of the 3 tennis balls = 3 x (4/3)π(1.3)3 = 33.3 cubic inches
Volume of the space NOT occupied by the tennis balls = 44.7 - 33.3 = 11.4 cubic inches
Rounded to the nearest tenth = 11.4 cubic inches
Tennis balls with a diameter of 2.6 inches are sold in cans of three. The can is a cylinder. What is the volume of the space NOT occupied by the tennis balls? (Assume the tennis balls touch the can on all sides, top and bottom.) Round to the nearest tenth and show all steps and reasoning.
2 answers
wrong again
The radius of the tennis ball and the cylinder is 1.3 for each
the height of the can must be 3(diameter of ball) = 3(2.6) = 7.8
volume of can = π r^2 h = π(1.3)^2 (7.8) = 41.4125 inches^3
volume of 3 tennis balls = 3(4/3)π (r^3)
= 4π(1.3)^3 = 27.6083
volume of empty space = 41.4125 - 27.6083 = appr 13.8 inches^3
Don't understand how this robot tutor can't do basic arithmetic
The radius of the tennis ball and the cylinder is 1.3 for each
the height of the can must be 3(diameter of ball) = 3(2.6) = 7.8
volume of can = π r^2 h = π(1.3)^2 (7.8) = 41.4125 inches^3
volume of 3 tennis balls = 3(4/3)π (r^3)
= 4π(1.3)^3 = 27.6083
volume of empty space = 41.4125 - 27.6083 = appr 13.8 inches^3
Don't understand how this robot tutor can't do basic arithmetic