LOL
F = G Me m/r^2
F/m = G Me/r^2 = 9.8
F/Me = G m/r^2 = 9.8 (m/Me)
so
9.8 (44/5.98*10^24)
Take the mass of the Earth to be 5.98 × 1024 kg.
If the Earth’s gravitational force causes a falling 44 kg student to accelerate downward at 9.8 m/s2, determine the upward accelera- tion of the Earth during the student’s fall.
Answer in units of m/s2.
1 answer