Your mass and radius of the Earth are not correct.
The Earth's radius is 6380 km .
F = Msat*Mearth*G/Rsat^2
= Msat* g * (Rearth/R)^2
Rsat = Rearth + 612 km = 6992 km
Re/R = 0.9125
g = 9.81 m/s^2
Hubble's weight in that orbit is
(0.9125)^2 = 83.3% of its weight on the Earth's surface.
The Hubble Space Telescope orbits the Earth at an approximate altitude of 612 km. Its mass is 11,100 kg and the mass of the Earth is 5.97×1024 kg. The Earth's average radius is 6.38×106 m. What is the magnitude of the gravitational force that the Earth exerts on the Hubble?
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