Table salt, NaCl(s), and sugar, C12H22O11(s), are accidentally mixed. A 4.00-g sample is burned, and 2.70 g of CO2(g) is produced. What was the mass percentage of the table salt in the mixture?

Answer 1

C12H22O11 + 12CO2 + 11H2O

mols CO2 = grams/molar mass = ?
mols sugar = mols CO2 x (1/12) = ?
grams sugar = mols x molar mass

4.00-g sugar = g salt
% salt = (g salt/4.00)*100 = ?