NaCl doesn't burn. Sugar does.
C12H22O11 + 12O2 ==> 12CO2 + 11H2O
Convert g CO2 to mols sugar.
2.90g CO2 x (molar mass sugar/12*molar mass CO2) = 2.90 x (342/12*44) = about 1.9
NaCl + sugar = 6.00
mass sugar = -1.9
mass NaCl = 6-1.9 about 4.1
%NaCl = (mass NaCl/mass sample)*100 = ?
%NaCl = about (4.1/6)*100 = about 68.7%
You should go through and do it more accurately. I've just estimated here and ther.
Table salt NaCl and sugar C12H22O11 are accidentally mixed. A 6.00 g sample is burned and 2.90 g of CO2 is produced. What was the mass percentage of the table salt mixture?
Could you please show me all the way through if you can?
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