Table salt, NaCl(s), and sugar, C12H22O11(s), are accidentally mixed. A 4.00-g sample is burned, and 3.30 g of CO2(g) is produced. What was the mass percentage of the table salt in the mixture?

Answer 1

Convert mass CO2 to mass C6H12O6.
3.30g CO2 x (molar mass C6H12O6/6CO2) = ?g C6H12O6.
Mass NaCl = 4.00 - ?g C6H12O6 = g NaCl
%NaCl = (g NaCl/4.00)*100 = ?