Asked by Nicole
Susan has some $2-coins and $5-coins. If there are 18 coins and the total amount of these coins is not less than $75, find the minimum number of $5-coins.
Answers
Answered by
hurrdurrbeedooda
Let x = 2$ coins
Let y = 5$ coins
First equation is for the total amount of coins:
x + y = 18
Second Equation is for total amount in dollars in total from the coins:
2x + 5y = $75
Lets isolate for y
x = 18 - y
Sub into second equation
2(18 - y) + 5y = 75
36 - 2y + 5y = 75
3y = 39
y = 13
Therefore, you must have at least 13 $5 coins.
Let y = 5$ coins
First equation is for the total amount of coins:
x + y = 18
Second Equation is for total amount in dollars in total from the coins:
2x + 5y = $75
Lets isolate for y
x = 18 - y
Sub into second equation
2(18 - y) + 5y = 75
36 - 2y + 5y = 75
3y = 39
y = 13
Therefore, you must have at least 13 $5 coins.
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