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hurrdurrbeedooda
Answers (19)
Umm, just add them together and divide by 2... 17.5 + 35 = 52.5... Divided by 2...26.25..
Find the net force of the two concurrent forces, and then reverse the direction of the net force. There's your equilibriant. SIMPLE ex: 2N east Equilibriant: 2N west
d = m/v d = 5g / 10cm3 d = 0.5 g/cm3
79N
Whats the equation? If point is just 1, then there is an undefined tangent. Since the tangent will be vertical.
Kinematic equation: d = vi*t + (1/2)a*t^2 Since its moving at 3.6m/s in the horizontal direction, disregard it. Hence initial velocity is 0 1.2m = 0 + (1/2)9.81m/s^2 * t^2 (1.2m / (1/2)9.81 m/s^2) = t^2 (1.2m / (1/2)9.81 m/s^2)^1/2 = t t = 0.49 s
Assuming acceleration is the force of gravity. Vf = Vi + a*t Vf = 18m/s + 9.81ms^-2 * 15s Vf = 165.15 m/s d = Vi*t + 1/2a*t^2 358 = 18m's*t + (1/2)9.81ms^-2 * t^2 Set it to zero: 0 = 4.91ms^-2 * t^2 + 18m/s * t - 358. Use quadratic formula t = 6.9s or t =
Ke (Kinetic Energy) = (1/2)m*v^2 m = mass v = speed u = 1.66 x 10^-27 kg 12u = 1.99 x 10^-26 kg Ke = (1/2)(1.99 x 10^-26 kg)*(2 x 10^6m/s)^2 Ke = 3.98 x 10^-12. Convert this to KeV or w/e.
F = kx ma = kx 480kg * (4*9.81) = k * 11.8m k = 1596.20339
EDIT: Change 250x = 5000 - 2500 to: 250x = 5000 - 2800
Let x = part - time staff Total cost for full-time workers = 350 * 8 = 2800 2800 + 250x = 5000 250x = 5000 - 2500 x = 8.8 Since I have not met 4/5'ths of a person we would have to either round up or down. Since the daily wage cannot exceed $5000 we will
Let x = 2$ coins Let y = 5$ coins First equation is for the total amount of coins: x + y = 18 Second Equation is for total amount in dollars in total from the coins: 2x + 5y = $75 Lets isolate for y x = 18 - y Sub into second equation 2(18 - y) + 5y = 75
Kinematic Equation d = Vi*t + 1/2a*t^2 Vi = Initial Velocity d = distance traveled a = acceleration t = time Since Vi is 0(he drops it). -Also converted 18 km to 18000m 18000 = 0 + 1/2(4.4)*t^2 18000 = 2.2*t^2 (18000/2.2) = t*2 (18000/2.2)^1/2 = t t = 90s
Lets get acceleration. Vf^2 = Vi^2 + 2a*d Vf = Final velocity Vi = Initial veloctiy a = acceleration d = distance traveled 0 = (120)^2 + 2a(0.90) a = -8000 Ava = (Vf - Vi/(Tf - Ti) First must find time. Ava = average acceleration Vf = Vi + a*T Tf = final
Hmm, based off of what I think. The rope will be holding the mass at an angle of 76 degrees with respect to a horizontal x- axis. Fg = 9.81 * 17 = 167N 167N sin 76
Be more specific with the chart
yes
Since the object is at the top of its trajectory its change in altitude (sin velocity) should be 0. Then you just need to calculate for the speed in the horizontal axis(which never changes in simple projectile motion). It becomes 141 cos(pi/4) or 141 cos
Inverse sin (8/150) will get you the angle. Ramp is the hypotenuse, entrance height is the opposite side of the triangle.
