To find the surface area of the net diagram of the right circular cylinder, we need to find the areas of the two circles and the rectangular side.
The area of a circle is πr^2, and since we are given that the radius is 10 inches, the area of each circle is 3.14 x 10^2 = 3.14 x 100 = 314 square inches.
The area of the rectangle is the base (which is the circumference of the circle, 2πr) multiplied by the height. The base is 2(3.14)(10) = 62.8 inches, and the height is 9 inches, so the area of the rectangle is 62.8 x 9 = 565.2 square inches.
Therefore, the total surface area of the net diagram of the right circular cylinder is 2(314) + 565.2 = 628 + 565.2 = 1193.2 square inches.
Surface Area of Cylinders Practice
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Question
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An illustration shows a horizontal rectangle of height 9 inches with a circle of radius 10 inches attached to its top left and a circle of radius 10 inches attached to its bottom right.
Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π .
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