a. Calculate mols AgNO3 needed. mols AgNO3 = grams/molar mass
b. 169.87
c. mols AgNO3 = M x L. You know M and mols solve for L and convert to mL.
Suppose you wanted to find out how many milliliters
of 1.0 M AgNO3 are needed to provide
169.88 g of pure AgNO3.
a. What is step 1 in solving the problem?
b. What is the molar mass of AgNO3?
c. How many milliliters of solution are needed?
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