2AgNO3 + K2Cr2O7 ==> 2KNO3 + Ag2CrO4
moles AgNO3 = M x L = ??
moles K2Cr2O7 = 1/2 x moles AgNO3
M K2Cr2O7 = moles/L
solve for L and convert to mL.
How many milliliters of 0.645 M K2CrO4 are needed to precipitate all the silver in 405 mL of 0.190 M AgNO3 as Ag2CrO4?
2 answers
49.01574803mL