Suppose you have a reaction that has a ΔH of +80 kJ and a ΔS of 215 J/K. At what temperature will this reaction change from being not spontaneous to spontaneous?

Question

31 C

99 C

-18 C

25 C

53 C

Answer 1

dG = dH - TdS
Set dG = 0 and solve for T in kelvin. Remember to make the units the same (they aren't now).