Going to the front of the class means going to the head of the class which means you have done a very very good job and you're at the top of the class. It's a very high compliment.
2AgNO3 + CaCl2 ==> 2AgCl + Ca(NO3)2
mols AgCl obtained = grams AgCl/molar mass AgCl = 0.4462/143.34 (but confirm that--I'm just reciting from memory) = approx 0.003
mols CaCl2 you started with = approx 0.003 x(1 mol CaCl2/2 mols AgNO3) = ?
%CaCl2 = (g CaCl2/mass sample)*100 = ?
Better confirm all those numbers and calculations.
Suppose you have a mixture that contains CaCl2, plus other compounds that do not react with AgNO3. If 0.2918
g of the mixture yields 0.4462 g of AgCl, what is the percentage of CaCl2 in the mixture (thats what was missing from the prior q). Also what did you mean when you said go to the front of the class?
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