To find the perimeter of the dilated triangle, you first need to determine the new side lengths by applying the scale factor of \( \frac{1}{3} \).
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Calculate the new side lengths:
- First side: \( 11 \times \frac{1}{3} = \frac{11}{3} \)
- Second side: \( 9 \times \frac{1}{3} = 3 \)
- Third side: \( 28 \times \frac{1}{3} = \frac{28}{3} \)
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Now, add the new side lengths to find the perimeter: \[ \text{Perimeter} = \frac{11}{3} + 3 + \frac{28}{3} \]
To add these, first convert 3 into a fraction with the same denominator (3): \[ 3 = \frac{9}{3} \]
Now the perimeter calculation is: \[ \text{Perimeter} = \frac{11}{3} + \frac{9}{3} + \frac{28}{3} = \frac{11 + 9 + 28}{3} = \frac{48}{3} = 16 \]
Therefore, the perimeter of the dilated triangle is 16 inches.