Suppose you add 92 ml of dilute acid to 46 ml of water. Both the water and acid were at room temperature (22 C) before being mixed. The temperature of the solution increased to 39 C. How much energy (in kJ) was released by the dissolution of the acid if the specific heat capacity of the solution is still the same as water 4.18 J/(g ·K) and the density was still approximately 1.0 g/ml. The error interval is +/- 5%.

Answer 1

energy=mass*specificheat*changetemp
= (92+46)grams*4.18J/gC*17C