Suppose Triangle ABC has right angle C. Find the measures of the other sides to the nearest whole number if...?
the measure of angle A is 32 degrees, and the measure of AB is 42.
For one side, I got 23, and for the other side, I got 35. Am I right?
4 answers
correct
thanks
Check rounding--I got slightly different values that rounded to different numbers.
Given:
C = 90 degrees
A = 32 degrees
AB = 42 units
Therefore, B = 180 - 90- 32 = 58 degrees
Sine rule:
BC/sin(A) = AC/sin(B) = AB/sin(C)
BC/sin(32) = AC/sin(58) = 42/sin(90)
BC/(0.5299) = AC/(0.8480) = 42/(1.0)
BC = (0.5299)(42) = 22.26 round to 22
AC = (0.8480)(42) = 35.62 round to 36
Given:
C = 90 degrees
A = 32 degrees
AB = 42 units
Therefore, B = 180 - 90- 32 = 58 degrees
Sine rule:
BC/sin(A) = AC/sin(B) = AB/sin(C)
BC/sin(32) = AC/sin(58) = 42/sin(90)
BC/(0.5299) = AC/(0.8480) = 42/(1.0)
BC = (0.5299)(42) = 22.26 round to 22
AC = (0.8480)(42) = 35.62 round to 36
I used an online graphing calculator..so maybe it's different like that?
1 answer