Asked by Coreen
Suppose the skin temperature of a naked person is 34 degree celsius when the person is standing inside a room whose temperature is 23 celsius. The skin area of the individual is 1.5m^2.
(a) Assuming the emissivity is 0.80, find the net loss of radint power from the body.
(b) Determine the number of food Calories of energy(1 food calorie=4186J) that is lost in one hour due to the net loss rate obtained in part (a0. Metabolic conversion of food into energy replaces this loss.
I will be happy to critique your thinking.
Ignore convection losses, which in fact are probably greater than radiation.
(a) Assuming the emissivity is 0.80, find the net loss of radint power from the body.
(b) Determine the number of food Calories of energy(1 food calorie=4186J) that is lost in one hour due to the net loss rate obtained in part (a0. Metabolic conversion of food into energy replaces this loss.
I will be happy to critique your thinking.
Ignore convection losses, which in fact are probably greater than radiation.
Answers
Answered by
Gsidthekid
Yeahh Go UBC
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