Asked by kelly
At body temperature the latent heat of vaporization of water is Lv = 2.26e3 kJ/kg.
(a) A naked person with a surface area A = 1.55 m2 and a skin temperature = 37.3 degrees is in a sauna room at T = 82.0 degrees. The person's skin has an emissivity e = 0.910. She evaporates sweat from her body to balance the rate of heat absorption by radiation.
(i) Neglecting any heat production due to metabolism, what is the net rate of heat absorption by the person due to radiation? in W
(ii) How much sweat must be evaporated per hour to balance a net rate of heat absorption of H = 0.850e3 W? in kg/hr
(a) A naked person with a surface area A = 1.55 m2 and a skin temperature = 37.3 degrees is in a sauna room at T = 82.0 degrees. The person's skin has an emissivity e = 0.910. She evaporates sweat from her body to balance the rate of heat absorption by radiation.
(i) Neglecting any heat production due to metabolism, what is the net rate of heat absorption by the person due to radiation? in W
(ii) How much sweat must be evaporated per hour to balance a net rate of heat absorption of H = 0.850e3 W? in kg/hr
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