Asked by uhh

Suppose the length and the width of the sandbox are doubled.



a. Find the percent of change in the perimeter.

The percent of change in the perimeter is a
% increase.

b. Find the percent of change in the area.

The percent of change in the area is a
% increase.
Answered by uhh
idk :P
Answered by Chloe
its so annoying they wont answer my question either
Answered by Ms. Sue
Please be patient. I can't help you, but math tutors should be on Jiskha within an hour or two.
Answered by Henry2
a. P1 = 2L + 2W. = 2(L+W).
P2 = 4L + 4W.= 4(L+W).
P2/P1 = 4(L+W)/2(L+W) = 2.0 = 200%.
200% - 100% = 100% Increase.

b. A1 = L * W.
A2 = 2L * 2W = 4(L*W).
A2/A1 = 4(L*W)/(L*W) = 4.0 = 400%.
400% - 100% = 300% Increase.
Answered by Savior
a. 100% increase
b. 300% increase

boom.
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