Asked by math (check answers)

there is a sandbox with a width of 6ft and a length of 10ft, suppose the length and the width are doubled.
a. find the percent of change in the perimeter
b. find the percent of change in the area
i think the answer is 66.67% for both of them
Answered by ruby
just realized i put my name in the subject and the subject in my name, oops!
Answered by Reiny
don't understand how you came up with that answer.

old sandbox : 6 by 10
so perimeter = 32 ft
area = 60 ft^2

new sandbox : 12 by 20
new perimeter = 64 --> it doubled, so a 100% increase, the multiplication factor is 2

new area = 240 ft^2 --> it quadrupled
so the increase is 300% , the multiplication factor was 4

in general, since perimeter is a linear measurement, the perimeter would be the same multiplication factor
and the area would be the (multiplication factor)^2

e.g. If we had tripled the dimensions, the area would be 9 times as large
Answered by Daniel
What about the perimeter?
Answered by Daniel
Oh wait I see it now sorry
Answered by ljhkkjh
ummm no... that didnt help
Answered by bob
not correct
Answered by hgyoiyukft
Imagine giving the wrong answer to everyone who actually needs help. Couldn't be ruby
Answered by bamananans
Didnt work
Answered by ddd
didnt work bout to post this on my insta and no one is ever going to use this website again
Answered by Bootcrack
Fdfdbtfhtrhtryhtyhthytyht
Answered by JAVIER
Its actually correct dummys
Answered by bruh
Lol at least Reiny actually gave the correct answer oh my flipping god
Answered by Jimmy
Whats the proportion
Answered by Anonymous
nobody is helping


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