Question

there is a sandbox with a width of 6ft and a length of 10ft, suppose the length and the width are doubled.
a. find the percent of change in the perimeter
b. find the percent of change in the area
i think the answer is 66.67% for both of them

Answer 1

just realized i put my name in the subject and the subject in my name, oops!

Answer 2

don't understand how you came up with that answer.

old sandbox : 6 by 10
so perimeter = 32 ft
area = 60 ft^2

new sandbox : 12 by 20
new perimeter = 64 --> it doubled, so a 100% increase, the multiplication factor is 2

new area = 240 ft^2 --> it quadrupled
so the increase is 300% , the multiplication factor was 4

in general, since perimeter is a linear measurement, the perimeter would be the same multiplication factor
and the area would be the (multiplication factor)^2

e.g. If we had tripled the dimensions, the area would be 9 times as large

Answer 3

What about the perimeter?

Answer 4

Oh wait I see it now sorry

Answer 5

ummm no... that didnt help

Answer 6

not correct

Answer 7

Imagine giving the wrong answer to everyone who actually needs help. Couldn't be ruby

Answer 8

Didnt work

Answer 9

didnt work bout to post this on my insta and no one is ever going to use this website again

Answer 10

Fdfdbtfhtrhtryhtyhthytyht

Answer 11

Its actually correct dummys

Answer 12

Lol at least Reiny actually gave the correct answer oh my flipping god

Answer 13

Whats the proportion

Answer 14

nobody is helping