suppose the experiment was conducted on the surface of the moon of about 1-6th that of the earth. If a single period takes exactly 1.00 second, how long does a period take on the moon ?

Answer 1

T^2 = 39.48 * L/g = 1^2 = 1.
L/g = 1/39.48, L = g/39.48 = 9.8/39.48 = 0.248 m.

On The Moon:
T^2 = 39.48*L/g = 39.48*0.248/1.63 = 6.0, T = 2.45 s.

Answer 2

Note: 39.48 = (2pi)^2.

Answer 3

suppose the experiment was conducted on the surface of the moon of about 1-6th that of the earth. If a single period takes exactly 1.00 second, how long does a period take on the moon ?