Suppose that R is the set of real numbers. Let f: R--> R be defined by f(x)= mx+b, where m and b are real numbers and m is nonzero. Prove that f is a bijection.

Answer 1

This kind of "new wave" math teaching will probably make it even harder to learn algebra. I hope not.

I had never heard of a bijection before. So I looked up this website:
http://en.wikipedia.org/wiki/Bijection

It seems obvious that for every x there is a unique f(x), and for every f(x) there is a unique x. That fulfills the requirement for a bijection.