Asked by Nick

Suppose that, on a day when the outside temperature is 15 degrees Celsius, we fill a balloon with pure nitrogen gas, of which the molar mass is 28 grams per mole. Now suppose that we want to heat up a second (equally large) balloon containing air, such that it generates the same amount of lift.

To what temperature (in degrees Celsius) should we heat up the second balloon?
Answered by kelly
L=ρVg(1−2828.97)=ρVg⋅0.0334829 is the lift of nitrogen to air

now T/(T+ΔT) for hot air balloon, the T is 288K and we know 15 celsius was outside temperature. so ΔT is 9.9 and add 15 gives about 25 C.
Answered by Anonymous
24.95
Answered by david
pls how did you arrive at this 24.95
Answered by Polat A.
David my brother ın my opinion he used air's molar constant but he didn't show you
Answered by Pala
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Answered by Aslan Akbey
Pala , you've sold us for money.
Answered by Pala
only the dead men see
Answered by Cerrrahpaşalı Halit
Çakır 39 count
Answered by Süleyman Çakır
count your ancestry too
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