L=ρVg(1−2828.97)=ρVg⋅0.0334829 is the lift of nitrogen to air
now T/(T+ΔT) for hot air balloon, the T is 288K and we know 15 celsius was outside temperature. so ΔT is 9.9 and add 15 gives about 25 C.
Suppose that, on a day when the outside temperature is 15 degrees Celsius, we fill a balloon with pure nitrogen gas, of which the molar mass is 28 grams per mole. Now suppose that we want to heat up a second (equally large) balloon containing air, such that it generates the same amount of lift.
To what temperature (in degrees Celsius) should we heat up the second balloon?
9 answers
24.95
pls how did you arrive at this 24.95
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