Suppose that
lim t→1 (f(t) − e^π)/ (t − 1) = 16.
What is limit→1 f(t)?
I don't understand, is f(1) = e^x? but how do I show it? am I allowed to rearrange that equation to f(t) = 16(t-1) +e^π inside of a limit? ughhhh I dont understand, any help is appreciated!
3 answers
what is the limit t→1 f(t)?**
note that at t=1, we have (f(1)-e^π)/(1-1) = 16
But division by zero is undefined, and the only way that limit can be 16 is if
f(1) - e^π is also zero.
So, lim(t->1) f(t) = e^π
But division by zero is undefined, and the only way that limit can be 16 is if
f(1) - e^π is also zero.
So, lim(t->1) f(t) = e^π
thank you!!