ok.
It appears to be in QIV, and is a 12-35-37 right triangle.
If you draw it correctly, you should be able just to read off the values of the trig functions of that angle.
Suppose that
θ
is an angle in standard position whose terminal side intersects the unit circle at
, 35/37−12/37
.
5 answers
ok, I am supposing Ø to be as you stated, now what?
did you notice that 35^2 + (-12)^2 = 37^2 ?
Do you know the basic trig ratios in terms of the x, y, and r of the corresponding right-angled triangle?
did you notice that 35^2 + (-12)^2 = 37^2 ?
Do you know the basic trig ratios in terms of the x, y, and r of the corresponding right-angled triangle?
no that why I ask
what will sin , cot, csc be for that >
sketch a right-angled triangle.
label the horizontal base as x
the vertical side as y
the hypotenuse as r, and the base angle as Ø
memorize these ratios:
sinØ = y/r
cosØ = x/r
tanØ = y/x
and now their reciprocals:
cscØ = 1/sinØ = r/y
secØ = 1/cosØ = r/x
cotØ = 1/tanØ = x/y
You will not be able to handle trig questions without knowing these.
label the horizontal base as x
the vertical side as y
the hypotenuse as r, and the base angle as Ø
memorize these ratios:
sinØ = y/r
cosØ = x/r
tanØ = y/x
and now their reciprocals:
cscØ = 1/sinØ = r/y
secØ = 1/cosØ = r/x
cotØ = 1/tanØ = x/y
You will not be able to handle trig questions without knowing these.
1 answer