A terminal position of ((-15/13),(12/13))
puts you in quadrant II and using similar triangles we could have the same angle for a terminal position at
(-5,4)
so r = √(25+16) = √41
x = -5, y = +4 , r = √41
sin è = 4/√41 ----> csc è = √41/4
tan è = =4/5
Suppose that è is an angle in standard position whose terminal side intersects the unit circle at ((-15/13),(12/13)).
Find the exact values of cscè, tanè, and sinè.
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