By using Kepler's Third Law p^2 = a^3 we plug the numbers in.
p^2 = 16AU^3
p^2 = 4096AU
Then by taking the square root on both sides of the equation you get p=64 years.
Suppose that future observations with a new telescope reveal a planet about 16 AU from a star whose mass is the same size as our sun's. How long does it take the planet to orbit the star?
2 answers
64au