(1/2) m v^2 =m g h
on earth g is about 9.8m/s^2
v^2 = 2 g h
v = sqrt (2 g h) = sqrt (2*9.8*h) = sqrt ( 19.6 h) ok so far
now
27.7 = sqrt (19.6 h)
27.7^2 = 19.6 h
767/19.6 = h
Suppose that an object is dropped from a height of h meters and hits the ground with a velocity of v meters per second. Then =v19.6h. If an object hits the ground with a velocity of 27.7 meters per second, from what height was it dropped?
Carry your intermediate computations to at least four decimal places, and round your answer to the nearest tenth.
1 answer