suppose that an isotope of uninhexium Uuh under goes a succession of seven a

-decay reactions what isotope would be the final product of these changes and show how u arrived at this answer and would the final product be a lanthanide,an actinide,atransition element or a typical element

Here is a web site that will let you see Uuh on the periodic table. I believe ti is element #116
www.webelements.com

I have answered this question twice in the last 3-4 days.
Remember an alpha particle is a He nucleus. That is 2He4.
So 7 alpha emissions would mean atomic number would be reduced by 7*2 = 14 and the mass number would be reduced by 7*4 = 28.

116Uuh292 ==>102X264 + 7 2He4. Note that the subscripts and superscripts must equal; i.e., the subscripts and superscripts on the left must equal to the sum of those on the right.
From the periodic table, find the element X. It will have an atomic number of 102. And its position in the periodic table will tell you if it is a lanthanide, actinide, etc. Post your thoughts if you need further assistance and explain in detail what you don't understand.

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