I have an isotope,

Question

292
uuh
116

this suffers seven successive alpha decay reactions, I know each for alpha decay reaction the isotope loses

4
He
2

so the atomic weight decreases by four, and the atomic number by 2...

None of the elements shown in the periodic table show an element with an atomic weight for the isotope here

which after 7 alpha reactions I have calculated to

264
No
102

is this right ???

all the stuff in the periodic tables shows a different number any advice please ..

Freddo

I answered this came question from someone about 3-4 days ago. The 102No^264 is correct. Only a few atoms of Uuh have been made and most of the chemistry is unknown. I expect that is why you don't see this particular isotope mentioned. But if you KNOW it goes through 7 alpha emissions, then this must be correct. How do you know it goes through 7 alpha emissions?

Hi

The question asks that you suppose this isotope undergoes a succession of seven alpha decay reactions.. and asks that you describe the final product which is an actinide...

Thanks

I hope you're correct! Otherwise, back to the drawing board for me!!!