Asked by Phillip
It takes about 10^16 years for just half the samarium-149 in nature to decay by alpha-particle emission. Write the decay equation, and find the isotope that is produced by the reaction.
Answers
Answered by
DrBob222
<sub>62</sub><sup>149</sup>Sm ==><sub>2</sub><sup>4</sup>He + X
In a decay reaction the subscripts must add up and superscripts must add up. Therefore, the atomic number (the subscript) must be 60 for X and the superscript (the mass number) must be 145. Use that information to identify element X and write the symbol for it in place of X. I'll redo this if the subscripts and superscripts mess up.
In a decay reaction the subscripts must add up and superscripts must add up. Therefore, the atomic number (the subscript) must be 60 for X and the superscript (the mass number) must be 145. Use that information to identify element X and write the symbol for it in place of X. I'll redo this if the subscripts and superscripts mess up.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.